ISOYear(inputDate)
Last updated August 04, 2005
Version: 1 | Requires: CF5 | Library: DateLib
Description:
As ISOWeek is to Week(), ISOYear returns the ISOYear of the date input. For 360 days a year, this will be the same as
Year(), but from the 29th Dec to 3rd Jan, is may be different. Dates in this range may be part of a week number of a year that differs to the actual year of the date.
Return Values:
Returns a string.
Example:
<cfloop index="x" from="1" to="8">
<cfset testDate = dateAdd("d",x,"28/Dec/2005")>
<cfoutput>
Date: #dateFormat(testDate,"dddd dd/mmm/yyyy")# CF:#year(testDate)# ISO:#ISOYear(testDate)#<br>
</cfoutput>
</cfloop>
Parameters:
Name | Description | Required |
---|---|---|
inputDate | The date to format. | Yes |
Full UDF Source:
/**
* Returns the ISO correct year of a given date, necessary for dates from 29th Dec to 3rd Jan.
*
* @param inputDate The date to format. (Required)
* @return Returns a string.
* @author Pete Gibb (peter.gibb@icaew.co.uk)
* @version 1, August 4, 2005
*/
function ISOYear(inputDate) {
var inputDay = dayOfWeek(inputDate);
var yearNo = year(inputDate);
/** If the inputdate IS 29th-31st December, the input year MAY need to be next year **/
if((dateFormat(inputDate,"ddmm") is "2912" and dayOfWeek(inputDate) eq 2)
or (dateFormat(inputDate,"ddmm") IS "3012" and listFind("2,3",dayOfWeek(inputDate),",") gt 0)
or (dateFormat(inputDate,"ddmm") IS "3112" and listFind("2,3,4",dayOfWeek(inputDate),",") gt 0))
{yearNo=year(inputDate)+1;}
/** If the inputdate IS 1st - 3rd January, the input year MAY need to be previous year **/
if((dateFormat(inputDate,"ddmm") is "0301" and dayOfWeek(inputDate) eq 1)
or (dateFormat(inputDate,"ddmm") IS "0201" AND listFind("1,7",dayOfWeek(inputDate),",") gt 0)
or (dateFormat(inputDate,"ddmm") IS "0101" and listFind("1,7,6",dayOfWeek(inputDate),",") gt 0))
{yearNo=year(inputDate)-1;}
return yearNo;
}
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